7p^2+42p-112=0

Solution for 7p^2+42p-112=0 equation:

7p^2+42p-112=0

a = 7; b = 42; c = -112;
Δ = b2-4ac
Δ = 422-4·7·(-112)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-70}{2*7}=\frac{-112}{14}
=-8
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+70}{2*7}=\frac{28}{14}
=2
$